Can an 80 watt laser cut metal?

21 Oct.,2024

 

Can an 80 watt laser cut metal?

Laser cutting is a technology that uses a laser beam to cut materials. The cutting process is computer controlled, and it directs the laser beam to the material being cut. The laser beam is generated by a laser source and focused on a beam through a lens. The laser beam is strong enough to melt or vaporize the material being cut, leaving a clean edge with minimal thermal damage to the surrounding material.

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Factors influencing the ability of laser cutting metal

  • One of the factors that determine a laser's ability to cut metal is its power output. Power output is measured in watts, and the higher the power output, the stronger the laser and the thicker the metal that can be cut. For example, an 80-watt laser can cut a very thin sheet of metal, but it may not be strong enough to cut a thicker sheet of metal.
  • The type of laser also affects the laser's ability to cut metal. In general, CO2 lasers are commonly used to cut thin foils made from ferrous materials. Different types of lasers have different power outputs, and some lasers are better suited for cutting metal than others.
  • The type of metal being cut is also an important factor in determining the laser's ability to cut metal. Some metals are easier to cut than others, and the thickness of the metal can also affect the cutting process. Thicker metals require more power to cut, and the laser beam must be more focused to avoid losing intensity as it penetrates the material.
  • One thing to note is that the 80 watt laser is suitable for cutting thin sheet metal, but may not be strong enough to cut thicker sheet metal because it is not strong enough to cut all types of metal.

Conclusion

In summary, an 80-watt laser can cut metal, but the thickness of metal that can be cut will depend on the type of laser and the type of metal being cut. Before you proceed with your cutting project, it is important to consider all of these factors and choose a laser that has sufficient power and capability to perform the task at hand.

What is the max thickness of material that the 80W laser ...

HOW DO I DETERMINE THE AMOUNT OF SCREW WEIGTH THAT MY MOTOR CAN HANDLE

If you are looking for more details, kindly visit Tiper.

There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

Effort = Sf + (Load/(2 x pi x (R/p) x Se))

where:
p = pitch of the screw
Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
R = radius of the lead screw


This formula is based on the "law of the machine"

The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

Example:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 13 = .08 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
Effort = 5 N + (90 N / (15.7))
Effort = 5 N + (5.73 N)
Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

With a bit of algebra, the formula can be rewritten to find the load:

Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

Another formula that does not consider friction at all:

Effort = (Load x p) / (2 x pi x R)

Lets see if we get similar results:

Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

Example for a 10 TPI 5 start (2 turns per inch) lead screw:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 2 = .5 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
Effort = 5 N + (90 N / (6.28 x 2 x .2))
Effort = 5 N + (90 N / (2.512))
Effort = 5 N + (35.83 N)
Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

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HOW DO I DETERMINE THE AMOUNT OF SCREW WEIGTH THAT MY MOTOR CAN HANDLE

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